Question 1 of 24
Which expression correctly defines magnification when image size and actual size are corresponding lengths in the same unit?
Show a hint
Magnification compares how large the representation is with the real specimen.
Cambridge IGCSE · Biology 0610
Use magnification = image size ÷ actual size, rearrange the relationship to find image or actual size, and convert accurately between millimetres and micrometres. Every example supplies all image, scale and unit information in words, so no measurement from an absent drawing is required. This original practice pack is limited to Cambridge IGCSE Biology 0610 section 2.2; microscope operation, field of view, resolution and cell-structure identification are excluded.
2026 / 2027 / 2028 · Academic review not recorded · Published 2026-09-08
AI-assisted practice — not independently academically reviewed. Answers may contain errors; check important results against your course materials.
Guided tutorial
17 lesson sections
Explanation
Magnification tells how many times larger an image is than the actual specimen. Use magnification = image size ÷ actual size. The image size is the measured size of the representation, while actual size is the real biological size. A magnification of ×200 means every length in the image is 200 times the corresponding real length; it does not mean that 200 mm has been added.
Magnification is a ratio of two lengths. When both lengths are written in the same unit, the units cancel, so magnification has no unit. Write it as ×200 or 200 times. The calculation applies to corresponding lengths: for example, compare an image's stated width with the specimen's actual width, not an image width with an actual length.
Explanation
Image measurements are often given in millimetres because a printed or on-screen image is large enough to measure that way. Actual cells and small specimens are often described in micrometres. Before using image size ÷ actual size, convert one value so both are in millimetres or both are in micrometres. Dividing unlike units gives a meaningless scale factor.
The exact conversion is 1 mm = 1000 μm. Multiply millimetres by 1000 to obtain micrometres, and divide micrometres by 1000 to obtain millimetres. For example, 0.045 mm = 45 μm, while 320 μm = 0.320 mm. Keep the zero before a decimal smaller than one to make the value easy to read.
Worked example
A printed image is stated to show a specimen at ×120. The corresponding specimen length measures 48 mm on that image. No resizing has occurred after the ×120 image was produced. Calculate the actual length. Rearrange the relationship: actual size = image size ÷ magnification.
Substitute values in millimetres: actual size = 48 mm ÷ 120 = 0.4 mm. To express this in micrometres, multiply by 1000: 0.4 × 1000 = 400 μm. Check by reversing the calculation: 0.4 mm × 120 = 48 mm, which reproduces the stated image length.
Explanation
Start from M = I ÷ A, where M is magnification, I is image size and A is actual size. To find actual size, use A = I ÷ M. To find image size, use I = M × A. These are rearrangements of the same relationship, so a substitution check can catch an accidental multiplication or division.
The direction should also make sense. At magnification greater than ×1, image size must be larger than actual size when both use the same unit. If a ×500 calculation makes the actual specimen larger than its image, revisit the operation and unit conversion before accepting the result.
Worked example
A biological structure has an actual stated length of 0.09 mm. Its corresponding length in an unresized image is 36 mm. Both values already use millimetres, so calculate magnification directly: magnification = image size ÷ actual size.
Magnification = 36 mm ÷ 0.09 mm = 400. The millimetre units cancel, so the result is ×400, not 400 mm. A reverse check gives 0.09 mm × 400 = 36 mm. The answer is also sensible because the image length is much larger than the actual length.
Worked example
A specimen is stated to be 25 μm long and is represented at ×600. Calculate its image length in millimetres. Convert the actual length first: 25 μm ÷ 1000 = 0.025 mm. There is no later resizing, and the stated magnification applies to this length.
Use image size = magnification × actual size: 600 × 0.025 mm = 15 mm. Equivalently, 600 × 25 μm = 15 000 μm, then 15 000 μm ÷ 1000 = 15 mm. Both routes agree, which checks the conversion and multiplication.
Explanation
A millimetre is the larger unit, so one millimetre contains one thousand micrometres. A numerical value becomes larger when a fixed length is changed from mm to μm: 0.072 mm becomes 72 μm. It becomes smaller when changed from μm to mm: 72 μm becomes 0.072 mm.
A reliable check is to ask whether the physical length changed. Unit conversion describes the same length in a different unit; it does not magnify the specimen. Writing the equality before calculating—such as 72 μm = 0.072 mm—helps prevent a factor-of-1000 error in the later formula.
Worked example
An unresized micrograph is stated to have magnification ×2500. A corresponding specimen width measures 75 mm on the image. Find the actual width in micrometres. The image measurement is supplied numerically, so no ruler or unseen micrograph is needed.
First calculate in millimetres: actual size = 75 mm ÷ 2500 = 0.03 mm. Then convert: 0.03 mm × 1000 = 30 μm. Check using one unit throughout: 75 mm is 75 000 μm, and 75 000 μm ÷ 2500 also equals 30 μm.
Explanation
A scale bar represents a known actual distance. If a prompt states both the bar's measured image length and the actual length represented, magnification can be found without seeing or measuring a diagram. Use the bar's image length ÷ the actual distance it represents, after converting both to the same unit.
Do not treat the printed bar length as the specimen's actual length. A bar measuring 10 mm that represents 25 μm compares 10 mm with 0.025 mm. It gives the image magnification. This pack always states the measured bar length, represented length, units and resizing status explicitly.
Worked example
A scale bar measures 8 mm on an image and is labelled as representing an actual distance of 20 μm. These measurements refer to the same displayed version, and the image has not been resized after the bar was measured. Find the magnification without relying on a drawing.
Convert 20 μm to millimetres: 20 ÷ 1000 = 0.020 mm. Magnification = 8 mm ÷ 0.020 mm = 400, so the image is at ×400. The same result follows in micrometres because 8 mm = 8000 μm and 8000 ÷ 20 = 400.
Explanation
The numerator and denominator must describe the same dimension. If a prompt gives image width, divide by actual width; if it gives image length, divide by actual length. Area magnification is a different idea and is not required here. A clearly stated numerical image length removes any dependence on line thickness, printer scaling or ruler placement.
Retain enough figures during intermediate work to avoid rounding drift, then report a sensible final value. Exact inputs such as 45 mm and ×900 produce an exact 0.05 mm in this pack. If a future measurement is approximate, the final size should not imply more precision than the measured image value supports.
Worked example
Specimen A has a stated image length of 24 mm at ×600. Specimen B has a stated image length of 18 mm at ×300. Both images are unresized, each length corresponds to the whole specimen being compared, and both image measurements are in millimetres. Determine which specimen is actually longer.
For A, actual length = 24 ÷ 600 = 0.04 mm = 40 μm. For B, actual length = 18 ÷ 300 = 0.06 mm = 60 μm. Therefore specimen B is actually longer, even though its image is shorter. Comparing image lengths alone would ignore their different magnifications.
Explanation
A calculation may be completed entirely in millimetres or entirely in micrometres. For example, an image length of 54 mm and an actual length of 720 μm can be compared by changing 720 μm to 0.72 mm, or by changing 54 mm to 54 000 μm. Either route gives the same magnification.
Avoid converting only part of a value or applying the 1000 factor twice. Write the converted equality on its own line, substitute labelled values, and include the × sign with magnification. A second route is useful as a check but is not required when the first calculation is already clear.
Explanation
Three checks are especially useful. First, at magnification greater than ×1, the image should exceed the actual size in matching units. Second, converting mm to μm multiplies the number by 1000, while converting μm to mm divides it by 1000. Third, substituting the calculated value back into the original formula should reproduce the given value.
Common wrong answers often reveal their cause. A result exactly 1000 times too large or too small suggests unmatched units. A reciprocal magnification smaller than one suggests image and actual size were reversed. An actual size equal to image size multiplied by magnification suggests the formula was rearranged incorrectly.
Worked example
An original image was at ×800 and showed a stated corresponding length of 20 mm. The entire image was then enlarged uniformly so every linear image measurement became 1.5 times as long; the specimen itself did not change. The displayed corresponding length is therefore 20 × 1.5 = 30 mm.
The displayed magnification changes by the same linear factor: 800 × 1.5 = ×1200. Check from actual size: the specimen length was 20 mm ÷ 800 = 0.025 mm. The displayed magnification is 30 mm ÷ 0.025 mm = 1200. The assumption of uniform linear enlargement is explicit; an area factor is not being used.
Explanation
A complete solution identifies what each number means, converts units where necessary, selects the correct rearrangement and gives a unit for a length. For magnification, use × notation rather than a length unit. This makes the reasoning auditable and helps distinguish a biological size from a picture measurement.
When an image is described as unresized, use its stated magnification directly. When a uniform linear resize factor is given, apply that factor to image lengths and magnification, not to actual specimen size. Never assume a print or screen scale that the question did not state; all tasks in this pack provide the needed numerical conditions.
Worked example
A specimen has an actual stated width of 3.2 μm and is represented at ×2500. The image is unresized and the requested answer is the corresponding image width in millimetres. Convert the actual width: 3.2 μm ÷ 1000 = 0.0032 mm.
Image size = 2500 × 0.0032 mm = 8 mm. Check in micrometres: 2500 × 3.2 μm = 8000 μm, and 8000 μm = 8 mm. The two routes agree, and an 8 mm image is appropriately much larger than a 3.2 μm specimen at ×2500.
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Question 1 of 24
Magnification compares how large the representation is with the real specimen.
Quick recall
Card 1 of 14
Front
Review the essentials
For every problem, label M, I and A; confirm that image and actual measurements describe corresponding lengths; and note whether resizing is explicitly stated. Convert I and A to the same unit. Then use M = I ÷ A, A = I ÷ M or I = M × A. Give actual or image size with a length unit and magnification with × notation.
Finish with a quick check. Convert between mm and μm using 1 mm = 1000 μm, substitute the answer back into the original relationship, and test whether its scale is plausible. All information in the practice questions is numerical and self-contained: no diagram, photograph, ruler measurement or hidden microscope setting is required.
Authorship: original ai assisted.
Original practice, not an official examination paper. Readnary is not affiliated with the awarding body. Prepared with AI assistance.